For a particle in uniform circular motion , the acceleration ` vec(a)` at a point ` p ( R, theta )` on the circle of radiu ` R` is ( Here ` theta` is measured from the ` x- axis` )

Options

A. `(v^(2))/(R )veci+(v^(2))/(R )vecj`
B. `-(v^(2))/(R )costhetaveci+(v^(2))/(R )sinthetavecj`
C. `-(v^(2))/(R )sinthetaveci+(v^(2))/(R )costhetavecj`
D. `-(v^(2))/(R )costhetaveci-(v^(2))/(R )sinthetavecj`

Answer

D

Explanation

`veca_(c)=a_(c) cos theta(-hati)+a_(c) sin theta(-hatj)`
`=-(v^(2))/(R ) cos theta hati-(v^(2))/(R )sin theta hatj`