A particle is kept fixed on as turntable rotating uniformly. As seen from the ground the particle goes in a circle,its speed is 20 cm/s and acceleration is 20 cm/s^2 The particle is now shifted to a new positon to make the radius half of the original value. The new values of the speed and acceleration will be

Options

A. `10cm//s,10cm//s^(2)`
B. `10cm//s,80cm//s^(2)`
C. `40cm//s,10cm//s^(2)`
D. `40cm//s,40cm//s^(2)`

Answer

A

Explanation

`V=romega,a=omega^(2)r`
`(a)/(v)=omegaimpliesomega=(20)/(20)=1rad//s,r=20cm`
`v'=(r )/(2)omega=(20)/(2)=10cm//s`
`a'=(r )/(2)omega^(2)=(20)/(2)=10 cm//s^(2)`