Three identical particles are joined together by a thread as shown in figure All the partical are moving in a horizontal plane If the vertical of the outermost particle is `v_(0)` then the ratio of tension in the three sections of the string `(T_(1):T_(2):T_(3) = ?)` is

Options

A. `3:5:6`
B. `3:4:5`
C. `6:9:10`
D. `7:6:11`

Answer

C

Explanation

`omega` will be same for three particles
`T_(1)-T_(2)=momega^(2)L` …`(i)`
`T_(1)-T_(3)=momega^(2)(3L)` …`(ii)` `T_(3)=momega^(2)(6L)`….`(iii)`
`T_(3)=6momega^(20L,T_(2)=9momega^(2)L,T_(1)=10momega^(2)L`
`T_(3):T_(2):T_(1)=6:9:10`