A stone is moved in a horizontal circle of radius `4m` by means of a string at a height of `20m` above the ground the string breaks and the particle files off horizontally, striking the ground `10m` away. The centripetal acceleration during circular motion is

Options

A. `6.25m//s^(2)`
B. `12.5m//s^(2)`
C. `18.75m//s^(2)`
D. `25m//s^(2)`

Answer

A

Explanation

`y=(gx^(2))/(2v^(2)implies20=(10(10)^(2))/(2v^(2)`
`v^(2)=25`
`a_(c)=(v^(2))/(R )=(25)/(4)=6.25m//s^(2)`