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In the previous problem (i) At theta=...

In the previous problem
(i) At `theta=cos^(-1)((2)/(3))`, the particle will lwave the hemisphere
(ii) At depth `R//3` below `A`, the particle will leave the hemisphere
(iii) At height `2R//3` above `O`, the particle will leave the hemisphere

A

`(i),(ii)`

B

`(ii),(iii)`

C

`(i),(iii)`

D

`(i),(ii),(iiii)`

Text Solution

Verified by Experts

The correct Answer is:
D

when `N=0,i.e., cos theta=2//3`
`theta=cos^(-1)((2)/(3))`, the block leaves hemisphere
`j=R(1-costheta)=(R )/(3)`
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