Two glass bulbs of equal volume are connected by a narrow tube and are filled with a gas at `0^@C` and a pressure of 76cm of mercury. One of the bulbs is then placed in melting ice and the other is placed in a water bath maintained at `62^@C`. What is the new value of the pressure inside the bulbs? The volume of the connecting tube is negligible.

Explanation

Since total number of moles remain same
`n_(1) + n_(2) = n'_(1) + n'_(2)`
`(P_(0) V)/(R T_(0)) + (P_(0) V)/(R T_(0)) = (P V)/(R T_(0)) + (P V)/(R T)`
`(2 P_(0))/(T_(0)) = P((1)/(T_(0)) + (1)/(T))`
`(2 xx 76)/((0 + 273)) = P((1)/(273) + (1)/(62 + 273))`
`(2 xx 76)/(273) = ((335 + 273)P)/(273 xx 335) = (608 P)/(273 xx 335)`
`P = (2 xx 76 xx 335)/(608) = 83.75" cm of Hg"`