A flask is filled with `13 g` of an ideal gas at `27^(@)C` and its temperature is raised to `52^(@)C`. The mass of the gas that has to be released to maintain the temperature of the gas in the flask at `52^(@)C`, the pressure remaining the same is

Options

A. `2.5 g`
B. `2.0 g`
C. `1.5 g`
D. `1.0 g`

Answer

D

Explanation

`PV = nRT = (MRT)/(M_(0))`
`PV = (13 R(27 + 273))/(M_(0)) = (M'R(52 + 273))/(M_(0))`
`M' = (13 xx 300)/(325) = 12 g`
Mass of gas released `= M - M' = 13 - 12 = 1g`