Gas at a pressure `P_(0)` in contained as a vessel. If the masses of all the molecules are halved and their speeds are doubles. The resulting pressure P will be equal to

Options

A. `4 P_(0)`
B. `2 P_(0)`
C. `P_(0)`
D. `(P_(0))/(2)`

Answer

B

Explanation

`P_(0) = (1)/(3)(MN)/(V) bar(v^2)`
`P = (1)/(3)((m//2)N)/(V)(4 bar(v^(2)))`
`(P)/(P_(0)) = 2 rArr = P = 2P_(0)`