The root mean square velocity of hydrogen molecules at 300 K is `1930 ms^(-1)`. The rms velocity of oxygen molecules at 1200 K will be

Options

A. `1930 m//s`
B. `965 m//s`
C. `3960 m//s`
D. `482.5 m//s`

Answer

B

Explanation

`((v_(rms))_(O_(2)))/((v_(rms))_(H_(2))) = sqrt(T_(O_(2))/T_(H_(2)) ((M_(0))_(H_(2)))/((M_(0))_(O_(2)))) =sqrt(1200/(300).2/32)=1/2`
`(v_("rms"))_(O_(2))=((v_("rms"))_(H_(2)))/(2)=1930/2=965 m//s`