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At what temperature is the root mean squ...

At what temperature is the root mean square velocity of gaseous hydrogen molecules is equal to that of oxygen molecules at `47^(@)C`?

A

`20 k`

B

`80 K`

C

`- 73 K`

D

`3 K`

Text Solution

Verified by Experts

The correct Answer is:
A

`(v_(rms))_(H_(2)) = (v_(rms))_(O_(2))`
`sqrt((3RT_(H_(2)))/((M_(0))_(H_(2)))) = sqrt((3 R T_(O_(2)))/((M_(0))_(O_(2))))`
`sqrt(T_(H_(2))/(2)) = sqrt(((273 + 47))/(32))`
`T_(H_(2)) = 20 K`
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