Two idential container joined by a small pipe initially contain the same gas at pressure `p_(0)` and absolute temperature `T_(0)`. One container is now maintained at the same temperature while the other is heated to `2T_(0)`. The common pressure of the gas

Options

A. `(3)/(2)p_(0)`
B. `(4)/(3)p_(0)`
C. `(5)/p_(0)`
D. `2 p_(0)`

Answer

B

Explanation

Number of moles remains same
`(p_(0)V_(0))/(RT_(0)) + (p_(0)V_(0))/(RT_(0)) = (pV_(0))/(RT_(0)) + (pV_(0))/(R.2T_(0))`
`2p_(0) = p + (p)/(2) = (3p)/(2)`
`p = (4p_(0))/(3)`