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In the previous question let V(0) be the...

In the previous question let `V_(0)` be the volume of each container. All other details remain the same. The number of moles of gas in the container at temperature `2 T_(0)` will be

A

`(p_(0)V_(0))/(2 RT_(0))`

B

`(p_(0)V_(0))/(RT_(0))`

C

`(2p_(0)V_(0))/(3 RT_(0))`

D

`(p_(0)V_(0))/(3 RT_(0))`

Text Solution

Verified by Experts

The correct Answer is:
D
`(pV_(0))/(R.2T_(0)) = (4p_(0)V_(0))/(3R.2T_(0)) = (2p_(0)V_(0))/(2RT_(0))`
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