If pressure of `CO_(2)` (real gas ) in a container is given by `P = (RT)/(2V - b) - (a)/(4b^(2))`, then mass of the gas in container is

Options

A. `11 g`
B. `22 g`
C. `33 g`
D. `44 g`

Answer

C

Explanation

van der Walls gas equation for `n` moles of real gas
`(P + (n^(2)a)/(V^(2))) (V - nb) = nRT`
`P = (nRT)/(V - nb) - (n^(2)a)/(V^(2)) = (RT)/((V)/(n) - b) - (a)/(V^(2)//n^(2))` (i)
Given equation
`P = (RT)/(2V - b) - (a)/(4b^(2))` (ii)
Comparing (i) and (ii)
`n = (1)/(2) = (M)/(M_(0)) = (M)/(44)`
`M = 22 g`