When 300 J of heat is added to `25 gm` of sample of a material its temperature rises from `25^(@)C` to `45^(@)C`. The thermal capacity of the sample and specific heat of the material are respectively given by

Explanation

`m=25g`,`Deltatheta=45-25=20^@C`,`DeltaQ=300J`
(a) Thermal capacity, `(DeltaQ)/(Deltatheta)=(300)/(20)=15J//.^(@)C`
(b) `ms=(DeltaQ)/(Deltatheta)`
`25xx10^-3s=1s`
Specific heat, `s=0.6xx10^3=600 J//Kg-^(@)C`
(c ) Number of holes `n=("mass")/("molecular mass")=(25)/(50)=(1)/(2)`
`DeltaQ=nCDeltatheta`
Molar heat capacity
`C=(DeltaQ)/(nDeltatheta)=(300)/((1//2)(20))=30J//"mole"^(@)C`