A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2 c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture is

Options

A. `(2//3) T`
B. `(8//5) T`
C. `(3//5) T`
D. `(3//2) T`

Answer

D

Explanation

Let equilibrium temperature be `theta`
`mC(2T-theta)=(m)/(2).2C(theta-T)`
`theta=(3T)/(2)`