In the previous question, if the specific latent heat of vaporization of water at `0^@C` is `eta` times the specific latent heat of freezing of water at `0^@C`, the fraction of water that will ultimately freeze is

Options

A. `(1)/(eta)`
B. `(eta)/(eta+1)`
C. `(eta-1)/(eta)`
D. `(eta-1)/(eta+1)`

Answer

B

Explanation

`m' L_(s)=m L_("ice")`
`m' eta L_("ice")=m L_("ice")`
`m'=m//eta`
`m/(m+m')=m/(m+m//eta)=eta/(eta+1)`