The vertical displacement of a block A in meter is given by `y=t^(2)//4` where t is in second. The downward acceleration `a_(B)` of a block B ( in `m//s^(2)`) is

Options

A. `2ms^(2)`
B. `1ms^(2)`
C. `4ms^(2)`
D. `9ms^(2)`

Answer

C

Explanation

`(d^(2)y)/(dt^(2))=(1)/(2)m//sec^(2),-TV_(B)+8TV_(A)=0`
`V_(B)=8V_(A)=8x(1)/(2)=4ms^(2),` .