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Under to action of force P the constant ...

Under to action of force `P` the constant acceleration of block `B` is `3ms^(-2)` to the right At the instant when the velcoity of `B` is `2ms^(-1)` to the right determine the absolute velocity of point `C` of the cable
.

A

`2`

B

`1`

C

`3`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
B
`-3TV_(B)+4TV_(A)=0, V_(A) =(3)/(4) V_(B) =(3)/(2)`
`(V_(B)+V_(C))/(2)=V_(A),V_(C)=2V_(A)-V_(B),V_(C)=3-2=1` .
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