A block of mass m is placed on a wedge The wedge can be accelerated in four manners marked as `(1),(2),(3)` and (4) as shown. If the normal reactions in situation `(1),(2),(3)` and (4) are `N_(1),N_(2),N_(3)` and `N_(4)` respectively and acceleration with which the block slides on the wedge in situation are `b_(1),b_(2),b_(3)` and `b_(4)` respectively then

Options

A. `N_(3)gtN_(1)gtN_(2)gtN_(4)`
B. `N_(4)gtN_(3)gtN_(1)gtN_(2)`
C. `b_(2)gtb_(3)gtb_(4)gtb_(1)`
D. `b_(2)gtb_(3)gtb_(1)gtb_(4)`

Answer

A, C

Explanation

Balancing forces perpendicular to incline `N_(1)=mg`
`cos37^(@)+ma sin 37^(@), N_(1) = (4)/(5) mg + (3)/(5)ma` and along incline `mg sin 37^(@)-ma cos 37^(@) =mb_(1)`
`b_(1) = (3)/(5) g - (4)/(5)a`
Similary of this case get `N_(2) = (4)/(5) mg - (3)/(5) ma`
and `b_(2) = (3)/(5) g + (4)/(5) a, N_(2) = (4)/(5) mg - (3)/(5) ma`
Similarly for this case get `N_(3) = (4)/(5) mg + (4)/(5)ma`
and `b_(3) = (3)/(5) g + (3)/(5)a`
Similarly for this case get `N_(4) = (4)/(5) mg - (4)/(5) ma`
and `b_(4) = (3)/(5)g -(3)/(5)a`





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