Home
Class 11
PHYSICS
In the above diagram all surface frictio...

In the above diagram all surface friction less what horizontal force has to be applied on wedge such in equilibrium steady state sping is compressed by `(mg sin theta)/(K)`
.

A

`2mg tan theta`

B

`2mg sin theta`

C

`4mg tan theta`

D

`2mg tan theta`

Text Solution

Verified by Experts

The correct Answer is:
C
applying newtons law among incline
`kx + mg sin theta = ma cos theta`
`2mg sin theta = (F)/(2) cos theta, 4mg tan theta =F`
.
Promotional Banner

Topper's Solved these Questions

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise SINGLE ANSWER QUESTIONS Passage -1|1 Videos

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise INTEGER TYPE QUESTIONS|23 Videos

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise NCERT BASED QUESTION|33 Videos

  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise Level 2 H.W|29 Videos

  • OSCILLATIONS

    NARAYNA|Exercise EXERCISE - IV|41 Videos

Similar Questions

Explore conceptually related problems

In the diagram given below all surfaces are frictionless. What horizontal force has to be applied on wedge such that in equilibium steady state spring is compressed by (mg sin theta)/k ?

Two bars of masses m_1 and m_2 connected by a non-deformed light spring rest on a horizontal plane. The coefficient of friction between the bars and the surface is equal to k. What minimum constant force has to be applied in the horizontal direction to the bar of mass m_1 in order to shift the other bar?

What force should be applied on the wedge so that block over it does not move? (All surfaces are smooth)

A wedge of mass m is placed on a horizontal smooth table. A block of mass m is placed at the mid point of the smooth inclined surface having length L along its line of greatest slope. Inclination of the inclined surface is theta= 45^(@) . The block is released and simultaneously a constant horizontal force F is applied on the wedge as shown. (a) What is value of F if the block does not slide on the wedge? (b) In how much time the block will come out of the incline surface if applied force is 1.5 times that found in part (a)

The friction coefficient between the two blocks shown in figure is mu but the floor is smooth. A. What maximum horizontal force F can be applied without disturbing the equilibrium of the systme? b.suppose the horizontal force applied is double of that found in part a. Findthe accelerations of the two masses.

Each of the two block shown in the figure has mass m. The pulley is smooth and the coefficient of friction for all surfaces in contact is mu . A constant horizontal force P applied in two cases shown in such a way that block A start just sliding then the value of minimum force P in case-I and case-II is :

A wedge of mass M makes an angle theta with the horizontal. The wedge is placed on horizontal frictionless surface. A small block of mass m is placed on the inclined surface of wedge. What horizontal force F must be applied to the wedge so that the force of friction between the block and wedge is zero ?

A wedge with mass M rests on a frictionless horizontal surface A block with mass m is placed on the wedge. There is no friction between the block and the wedge. A horizontal force f is applied to the wedge. What magnitude F must have if the block is to remain at constant height above the table top?

NARAYNA-NEWTONS LAWS OF MOTION-SINGLE ANSWER QUESTIONS
  1. A particle of mass m starts moving at t =0 due to force F =F(0) sin om...

    Text Solution

    |

  2. From the given, choose the correct option .

    Text Solution

    |

  3. In the diagram shown, the acceleration of the block B as shown in rela...

    Text Solution

    |

  4. In the pulley system shown the movable pulleys A,B and C have mass m e...

    Text Solution

    |

  5. A block of mass m is placed on a wedge The wedge can be accelerated in...

    Text Solution

    |

  6. A body of mass m =18kg is placed on an inclined plane the angle of inc...

    Text Solution

    |

  7. A body of mass m =18kg is placed on an inclined plane the angle of inc...

    Text Solution

    |

  8. Two smooth block are placed at a smooth corner as shown in fig. Both t...

    Text Solution

    |

  9. Two smooth block are placed at a smooth corner as shown in fig. Both t...

    Text Solution

    |

  10. Two smooth block are placed at a smooth corner as shown in fig. Both t...

    Text Solution

    |

  11. In the figure heavy mass m moves down the smooth surface of a wedge ma...

    Text Solution

    |

  12. A weightless inextensible rope rests on a stationary wedge forming an ...

    Text Solution

    |

  13. Block is attached to system of springs. Calculate equivalent spring co...

    Text Solution

    |

  14. Block A and C starts from rest and move to the right with acceleration...

    Text Solution

    |

  15. In the arrangement shown in fig. m(1)=1kg, m(2)=2 kg. Pulleys are mass...

    Text Solution

    |

  16. Find equivalent spring constant for the system .

    Text Solution

    |

  17. In the figure the wedge is pushed with an acceleration of sqrt3 m//s ^...

    Text Solution

    |

  18. In the above diagram system is in equilibrium if applied force F is do...

    Text Solution

    |

  19. In the above diagram all surface friction less what horizontal force h...

    Text Solution

    |

  20. If the above diagram initially there is no elongation in spring if the...

    Text Solution

    |