Six identical particles each of mass m a...

Six identical particles each of mass `m` are arranged at the corners of a regular hexagon of side length `L`. If the mass of one of the particle is doubled, the shift in the centre of mass is

`L/8`

`(sqrt(3)L)/8`

`(3L)/16`

`(3L)/4`

Text Solution

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The correct Answer is:

`shift=(md)/(M+m)`

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