A proton of velocity `(3hati+2hatj) ms^(-1)` enters a field of magnetic induction in the proton in (specific charge of proton `=0.96xx10^(8) Ckg^(-1)`) `[F=q(vec(v)xxvec(B))]`

Options

A. `0.96xx10^(8)(6hati+9hatj+4hatk)`
B. `0.96xx10^(8)(6hati-9hatj-4hatk)`
C. `0.96xx10^(8)(hati-hatj-hatk)`
D. `0.96xx10^(8)(5hati-9hatj-4hatk)`

Answer

B

Explanation

`vec(F)=e(vec(V)xxvec(B)), vec(a)=e/m(vec(v)xxvec(B))`