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A heavy wheel of radius 20 cm and weight...

A heavy wheel of radius `20 cm` and weight `10 kg` is to be dragged over a step of height `10 cm`, by a horizontal force `F` applied at the centre of the wheel. The minimum value of `F` is

A

`20 kg w t`

B

`1 kg wt`

C

`10 sqrt(3) k g w t`

D

`10sqrt(2) kg wt`

Text Solution

Verified by Experts

The correct Answer is:
C
Clockwise torque=anticlockwise torque
`mgsqrt((20)^(2)-(10)^(2))=F(20-10)`
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