The moment of inertia of a wheel of radi...

The moment of inertia of a wheel of radius `20 cm` is `40 kgm^(2)` if a tangential force of `80 N` applied on the wheel, its rotational `K.E.` after `4s` is

`16.2J`

`51.2J`

`25.6 J`

`24.8J`

Text Solution

Verified by Experts

The correct Answer is:

`omega=omega_(0)+alphat, KE=1/2Iomega^(2)`

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