An initial momentum is imparted to a homogenous cylinder, as a results of which it begins to roll without slipping up an inclined plane at a speed of `v_(0)=4m//sec` the plane make an angle `theta=30^(@)` with the horizontal. What height `h` will be the cylinder rise to? `(g=10 m//s^(2))`

Options

A. `0.8 m`
B. `1.2m`
C. `1.0m`
D. `1.6 m`

Answer

B

Explanation

`a=(g sin theta)/(1+(k^(2))/(R^(2))), v=sqrt(2aS),sin theta=h/s`