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A particle P collides elastically at M w...

A particle `P` collides elastically at `M` with a speed `v`. The change in angular momentum the particle about the point `N` during collision is

A

`2 mvl cos thetadarr`

B

`2mvl cos theta uarr`

C

zero

D

`mvl cos theta uarr`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaL=mv sin thetaxxl("taking component durring strike")-mv sin thetal=0`
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