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One end of an ideal spring of unstreched...

One end of an ideal spring of unstreched length `l_(O)=1m`, is fixed on a frictionless horizontal table. The other end has a small disc of mass `0.1 kg` attached to it. The disc is projected with a velocity `upsilon_(0)=11 m//s` perpendicular to the spring.

What is the force constant of spring?

A

`210 N//m`

B

`100N//m`

C

`110 N//m`

D

`200 N//m`

Text Solution

Verified by Experts

The correct Answer is:
A

Angular momentum of disc about fixed end is conserved, as the spring forces passes througn `O` `m upsilon_(0)l_(0)=m upsilon_(1)((11l_(0))/10),upsilon_(1)=10m//s=(10upsilon_(0))/11`
From conservation of energy we get
`1/2mV_(0)^(2)=1/2mV_(1)^(2)+1/2K_(2)((l_(0))/10)^(2)`
`rArrK_(2)=210 N//m`
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