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A thin wire of cross section a is made t...

A thin wire of cross section a is made to from a flexible circular loop of radius `R`. If the loop spins with angular speed `omega`, the (Assume `rho` = density and `y` = Young's modulus fo wire)

Tension in the wire is

A

`(mR omega^(2))/(2pi)`

B

`(2mR omega^(2))/(pi)`

C

`(mR omega^(2))/(4pi)`

D

`(1)/(2) m R omega^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A


`2T sin. (d theta)/(2) = dm R omega^(2), T d theta = dm R omega^(2)`
`T = int_(0)^(n pi) d theta = int_(0)^(m) dm R omega^(2), T = (m R omega^(2))/(2pi)`
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Knowledge Check

  • A thin wire of cross section a is made to from a flexible circular loop of radius R . If the loop spins with angular speed omega , the (Assume rho = density and y = Young's modulus fo wire) Stress in the wire is

    A
    `rho R^(2) omega^(2)`
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    `(1)/(2L) sqrt((Yl)/(rhoL))`
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