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A thin wire of cross section a is made t...

A thin wire of cross section a is made to from a flexible circular loop of radius `R`. If the loop spins with angular speed `omega`, the (Assume `rho` = density and `y` = Young's modulus fo wire)

Stress in the wire is

A

`rho R^(2) omega^(2)`

B

`rho R omega`

C

`(R^(2) omega^(2))/(rho)`

D

`(R^(2) omega^(2))/(2 rho)`

Text Solution

Verified by Experts

The correct Answer is:
A
`p = (m R omega^(2))/(2pi A) = (V rho R omega^(2))/(2pi A) = (A(2pi R)rho R omega^(2))/(2pi A) = rho R^(2) omega^(2)`
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