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If a body floats with (m//n)^(th) of its...

If a body floats with `(m//n)^(th)` of its volume above the surface of water, then the relative density of the material of the body is

A

`((n-m))/(n)`

B

`(m)/(n)`

C

`(n)/(m)`

D

`((n-m))/(n)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the relative density of a body that floats with a fraction of its volume above the surface of water. Let's denote the following: - Let \( V \) be the total volume of the body. - The volume of the body above the surface of water is given as \( \frac{m}{n} V \). - Therefore, the volume of the body submerged in water is \( V_{sub} = V - \frac{m}{n} V = V \left(1 - \frac{m}{n}\right) \). ### Step-by-Step Solution: 1. **Identify the Volume Submerged**: \[ V_{sub} = V \left(1 - \frac{m}{n}\right) \] 2. **Apply Archimedes' Principle**: According to Archimedes' principle, the weight of the water displaced by the submerged part of the body is equal to the weight of the body itself. \[ \text{Weight of the body} = \text{Weight of the water displaced} \] The weight of the body can be expressed as: \[ W_{body} = \text{Density of the material} \times V \times g \] The weight of the water displaced is: \[ W_{displaced} = \text{Density of water} \times V_{sub} \times g \] 3. **Substitute the Volume Submerged**: Substitute \( V_{sub} \) into the equation for the weight of the water displaced: \[ W_{displaced} = \text{Density of water} \times \left(V \left(1 - \frac{m}{n}\right)\right) \times g \] 4. **Set the Weights Equal**: Equate the two expressions for weight: \[ \text{Density of material} \times V \times g = \text{Density of water} \times \left(V \left(1 - \frac{m}{n}\right)\right) \times g \] 5. **Cancel Out Common Terms**: Since \( g \) and \( V \) are common in both sides, we can cancel them: \[ \text{Density of material} = \text{Density of water} \times \left(1 - \frac{m}{n}\right) \] 6. **Calculate Relative Density**: The relative density (specific gravity) is defined as the ratio of the density of the material to the density of water: \[ \text{Relative Density} = \frac{\text{Density of material}}{\text{Density of water}} = 1 - \frac{m}{n} \] ### Final Answer: The relative density of the material of the body is: \[ \text{Relative Density} = 1 - \frac{m}{n} \]

To solve the problem, we need to find the relative density of a body that floats with a fraction of its volume above the surface of water. Let's denote the following: - Let \( V \) be the total volume of the body. - The volume of the body above the surface of water is given as \( \frac{m}{n} V \). - Therefore, the volume of the body submerged in water is \( V_{sub} = V - \frac{m}{n} V = V \left(1 - \frac{m}{n}\right) \). ### Step-by-Step Solution: ...
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