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A liquid is kept in a cylindrical jar, which is rotated about the cylindrical axis. The liquid rises at its sides. The radius of the jar is `r` and speed of rotation is `Omega` the difference in height at the centre and the sides of the jar is

A

`(r^(2)omega^(2))/(g)`

B

`(r^(2)omega^(2))/(2g)`

C

`(g)/(r^(2)omega^(2))`

D

`(2g)/(r^(2)omega^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

Difference in potential energy `u=` rotational
Kinetic energy `becausemg(h_(1)-h_(2))=(1)/(2)Iomega^(2)`
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