Home
Class 11
PHYSICS
If the shearing stress between the horiz...

If the shearing stress between the horizontal layers of water in a river is 1.5 milli `"newton"//m^(2)` and `eta_("water")=1xx10^(-3)Pa.s` The velocity gradient is …`s^(-1)`

A

1.5

B

3

C

0.7

D

1

Text Solution

Verified by Experts

The correct Answer is:
A

`(dv)/(dx)=(F)/(Aeta)`
Promotional Banner

Topper's Solved these Questions

  • MECHANICAL PROPERTIES OF FLUIDS

    NARAYNA|Exercise Level 2 (C.W)|40 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    NARAYNA|Exercise Level 3|29 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    NARAYNA|Exercise C.U.Q|117 Videos
  • MATHEMATICAL REVIEW & PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|13 Videos
  • MECHANICAL PROPERTIES OF SOLIDS

    NARAYNA|Exercise LEVEL-II (H.W)|24 Videos

Similar Questions

Explore conceptually related problems

The velocity of water in a river is 2ms at the surface.If the river is 2m deep the shearing stress between the horizontal layers of water assuming bottom layer at rest ( eta=10^(-3) S I units for water)

The velocity of water in a river is 18 kmph near the surface. If the river is 4 m deep, the shearing stress between horizontal layers of water in Nm^(-2) is (eta_("water")=1xx10^(-3)pa.s)

A river 10 m deep is flowing at 5ms^(-1) . The shearing stress between horizontal layers of the rivers is ( eta=10^-(3) SI units)

The velocity of water in a river is 18 km/h near the upper surface. The river 5 m deep. What is the shearing stress between the horizontal layers of water ? (Coefficient of viscosity of water= 10^(- 2) Poise)

The velocity of water in a rier is 18kmh^-1 near the surface. If the river is 5 m deepm, find the shearing stress between the horizontal lyers of water. The coefficient of viscosity of water =10^-2 poise.

The relative velocity of two parallel layers of water is 8 cm/sec. If the perpendicular distance between the layers is 0.1 cm, then velocity gradient will be

The velocity of water near a river's surface is 20 km/hr. If the depth of the river is 4 m, calculate the shearing stress between the horizontal layers of water. Take, coefficient of viscosity of water = 0.01 poise.

When a liquid flows in a tube, there is relative motion between adjacent layers of the liquid. This force is called the viscous force which tends to oppose the relative motion between the layers of the liquid. Newton was the first person to study the factors that govern the viscous force in a liquid. According to Newton’s law of viscous flow, the magnitude of the viscous force on a certain layer of a liquid is given by F = - eta A (dv)/(dx) where A is the area of the layer (dv)/(dx) is the velocity gradient at the layer and eta is the coefficient of viscosity of the liquid. A river is 5 m deep. The velocity of water on its surface is 2 ms^(-1) If the coefficient of viscosity of water is 10 ^(-3 ) Nsm ^(-2) , the viscous force per unit area is :

The velocity of water in river is 180 km h^(-1) near the surface .If the river is 5 m deep,then the shearing stress between the surface layer and the bottom layer is ( cofficient of viscosity of water eta =10^(-3) Pa s)

The velocity of water in a river is 72 km h^(-1) near the surface. If the river is 4 m deep, find the shearing stress between horizontal layers of water. Coefficient of viscosity of water = 0.01 poise.

NARAYNA-MECHANICAL PROPERTIES OF FLUIDS-Level 1 (C.W)
  1. There is a hole at the side-bottom of a big water tank. The area of th...

    Text Solution

    |

  2. The flow rate from a tap of diameter 1.25 cm is 3 L//min. The coeffici...

    Text Solution

    |

  3. If the shearing stress between the horizontal layers of water in a riv...

    Text Solution

    |

  4. A force of 10 N is requrid to draw rectangular glass plate on the surf...

    Text Solution

    |

  5. Water is flowing through a capillary tube at the rate of 20xx10^(-6)m^...

    Text Solution

    |

  6. An artery in a certain person has been widened 1(1)/(2) times the orig...

    Text Solution

    |

  7. Water flowing from a hose pipe fills a 15 litre container in one minut...

    Text Solution

    |

  8. Two liquids are allowed to flow through two capillary tubes of length ...

    Text Solution

    |

  9. The viscous resistance of a tube to liquid flow is R. its resistance f...

    Text Solution

    |

  10. Eight spherical rain drops of the same mass and radius are falling dow...

    Text Solution

    |

  11. The velocity of small ball of mass M and density d(1) when dropped a c...

    Text Solution

    |

  12. The length of a rubber cord floating on water is 5 cm. The force neede...

    Text Solution

    |

  13. Calculate the force required to separate the galss plates of area 10^(...

    Text Solution

    |

  14. A thin wire ring of 3 cm radius float on the surface of liquid. The pu...

    Text Solution

    |

  15. A wire is bent in the form of a U-shape and a slider of negligible mas...

    Text Solution

    |

  16. A ring of inner and outer radii 8 and 9 cm is pulled out of water surf...

    Text Solution

    |

  17. In Fig(i) a thin film supports a small weight 3.5xx10^(-2)N The weight...

    Text Solution

    |

  18. Work of 6.0xx10^(-4)N joule is required to the done in increasing the ...

    Text Solution

    |

  19. The work done in increasing the radius of a soap bubble from 4 cm to 5...

    Text Solution

    |

  20. A mercury drop of radius 1 cm is sprayed into 10^(6) drops of equil s...

    Text Solution

    |