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Pressure inside two soap bubbles are 1.0...

Pressure inside two soap bubbles are `1.01` and `1.02` atmospheres. Ratio between their volumes is

A

`102:101`

B

`(102)^(3):(101)^(3)`

C

`8:1`

D

`2:1`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaP=(4T)/(R),(V=(4)/(3)piR^(3),RpropV^((1)/(3)))`
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