In the arrangement shown in the figure `(m_(A))/(m_(B))=(2)/(3)` and the ratio of density of block B and the liquid is `2:1` The system is released from rest. Then

Options

A. block B will oscillate but not simple harmonically
B. block B will oscillate simple harmonically
C. the system will remain in equilibarium
D. None of the above

Answer

A

Explanation

Let `m_(A)=2m,m_(B)=3m`
When block `-B` is inside the liquid
`a_(1)=(m_(A)g-(m_(B)g-"upthrust on B"))/(m_(A)+m_(B))=(g)/(10)`
When block `-B` is outside the liquid
`a_(2)=(m_(B)g-m_(A)g)/(m_(A)+m_(B))=(3mg-2mg)/(5m)=(g)/(5)`
Since `a_(1)&a_(2)` are constant, motion is periodic, but not simple harmonic