A hemispherical portion of radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cylinder is V and its mass M. It is suspended by a string in a liquid of density `rho` where it stays vertical. The upper surface of the cylinder is at a depth h below the liquid surface. The force on the bottom of the cylinder by the liquid is

Options

A. `rhog(V+piR^(2)h)`
B. `Mg`
C. `Mg-Vrhog`
D. `Mg+piR^(2)hrhog`

Answer

A

Explanation

Upthrust `=F_(2)-F_(1),F_(2)=F_(2)+` upthrust
`=rhogh(piR^(2))+Vrhog,rhog(V_piR^(2)+h)`