Consider a horizontally oriented syringe containing water located of a height of `1.25 m` above the ground. The diameter of plunger is `8 mm` and the diameter if the nozzle is `2 mm`. The plunger is pushed with a constant speed of `0.25 m//s`. Find the horizontal range of water stream on the ground. Take `g = 10 m//s^2`.
.

Options

A. 4 m
B. 6 m
C. 2 m
D. 8 m

Answer

C

Explanation

By `Av=` constant
We get `v=4m//s` the velocity of water coming out of the syringe.
Equation of parabolic trajectory of the water under gravity is given by
`y=xsintheta-(gx^(2))/(2u^(2)cos^(2)theta)`
`impliesR=2m`