Between a plate of area `100 cm^(2)` and another plate of area `100 m^(2)` there is a `1 mm`, thick layer of water, if the coefficient of viscosity of water is `0.01` poise, then the force required to move the smaller plate with a velocity `10 cms^(-1)` with reference to large plate is

Options

A. 100 dyne
B. `10^(4) `dyne
C. `10^(6)` dyne
D. `10^(9)` dyne

Answer

A

Explanation

`F=etaA(dv)/(dx)`
Where `A=100cm^(2),(dv)/(dx)=(10(cm)/(s))/(1mm)=100s^(-2)`