A vertical communicating tube contains a liquid of density `rho`. If it moves with a horizontal acceleration `a`, pressure at `A` is equal to :

Options

A. `rhogh_(2)+P_(0)+(2T)/(r_(2))+rhoal`
B. `rhogh_(2)+rhoal+P_(0)-(2T)/(r_(2))`
C. `rhogh_(1)+P_(0)-(2T)/(r_(1))`
D. `rhogh_(1)-P_(0)-(2T)/(r_(1))`

Answer

C

Explanation

in the direction of acceleration pressure decreases.