A capillary of the shape as shown is dipped in a liquid. Contact angle between the liquid and the capillary is `0^@` and effect of liquid inside the mexiscus is to be neglected. `T` is surface tension of the liquid, `r` is radius of the meniscus, `g` is acceleration due to gravity and `rho` is density of the liquid then height `h` in equilibrium is:

Options

A. Greater than `(2T)/(rrhog)`
B. Equal to `(2T)/(rrhog)`
C. less than `(2T)/(rrhog)`
D. of any value depending upon actual values

Answer

C

Explanation

As weight of liquid in capillary is balanced by surface tension then `T=2pir=pir^(2)h,pg` (for uniform r radius tube) But weight of liquid in tapered tube is more than uniform tube of radius r, then in order to balance is `lth_(1)`
`,h_(1)lt(2T)/(rpg)`