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Two vertical parallel glass plates are partially submerged in water. The distance between the plates is d and the length is `l`. Assume that the water between the plates does not reach the upper edges of the plates and the wetting is complete. The water will rise to height (`rho=` density of water and `alpha =` surface tension of water)

A

`(2sigma)/(rhogh)`

B

`(sigma)/(2rhogd)`

C

`(4sigma)/(rhogd)`

D

`(5sigma)/(rhogd)`

Text Solution

Verified by Experts

The correct Answer is:
A
Total upward force dur to surface tension `=2sigmal`
Weight of lifted liquid `=(hld)rhog`
Equating we get `h=(2sigma)/(rhogd)`
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