Water is flowing through a capillary tube at the rate of `20xx10^(-6)m^(3)//s`. Another tube of same radius and double the length is connected in series to the first tube. Now the rate of flow of water in `m^(3)s^(-1)` is

Options

A. `20xx10^(-6)`
B. `40xx10^(-6)`
C. `0`
D. `10xx10^(-6)`

Answer

4

Explanation

`Q=alpha(1)/(l),(Q_(1))/(Q_(2))=(2l)/(l)`