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The work done to get n smaller identical...

The work done to get n smaller identical drops to form a big spherical drop of water is proportional to

A

`(1)/(n^((2)/(3))-1)`

B

`(1)/(n^((2)/(3))-1)`

C

`n^((1)/(3))-1`

D

`n^((4)/(3))-1`

Text Solution

Verified by Experts

The correct Answer is:
3

`W=4piR^(2)T(n^((1)/(3))-1)`
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