Two liquid drops of radii 1 mm and 2 mm ...

Two liquid drops of radii 1 mm and 2 mm merge in vacuum isothermally. Radius of resulting drop is

`3mm`

`3^(1//3) mm`

`3^((2)/(3))`mm

6mm

Text Solution

Verified by Experts

The correct Answer is:

`R^(3)=r_(1)^(3)+r_(2)^(3)`

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