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The power radiated by a black is P and i...

The power radiated by a black is `P` and it radiates maximum energy around the wavelength `lambda_(0)` If the temperature of the black body is now changed so that it radiates maximum energy around a wavelength `3lambda_(0)//4` the power radiated by it will increase by a factor of .

A

`4//3`

B

`16//9`

C

`64//27`

D

`256//81`

Text Solution

Verified by Experts

The correct Answer is:
D
`P=sigmaAT^(4)` and `lambda_(m)T=const(P_(2))/(P_(1))=((T_(2))/(T_(1)))^(4)`
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