A body cools down from 50^(@)C to 45^(@)...

A body cools down from `50^(@)C` to `45^(@)C` in `5` minutes and to `40^(@)C` in another `8` minutes. Find the temperature of the surrounding.

`34^(@)C`

`30^(@)C`

`43^(@)C`

`37^(@)C`

Text Solution

Verified by Experts

The correct Answer is:

`(d'theta)/(dt)=K((theta_(1)+theta_(2))/(2)-theta_(0))`

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