A calorimeter of water equivalent `5g` has water of mass `55g` upto a certain level Another identical calorimeter has a liquid of mass '38g' upto same level As both of them cool in the same surrounding from `50^(@)C` to `46^(@)C` water takes `80s` where as the liquid takes `32s` to cool. If the specific heat of water is `1cal//g-.^(@)C` the specific heat of the liquid in `cal//g-.^(@)C` is .

Options

A. `0.8`
B. `0.4`
C. `0.5`
D. `0.2`

Answer

C

Explanation

From Newton's law of cooling
`(d theta)/(dt)prop(1)/(ms)rArrtpropms`
`:.(W+m_(1)s_(1))/(W+m_(2)s_(2))=(t_(1))/(t_(2)),W=` thermal capacity calorimeter .