Home
Class 11
PHYSICS
Specific heat of aluminum is 0.25 cal//g...

Specific heat of aluminum is `0.25 cal//g^(0)c`. The water equivalent of an aluminum vessel of mass one kilogram is

A

`40 cal//^(0)C`

B

`250 g`

C

`250 cal//^(0) C`

D

`40 g`

Text Solution

AI Generated Solution

The correct Answer is:
To find the water equivalent of an aluminum vessel with a mass of 1 kilogram, we can follow these steps: ### Step 1: Understand the Concept of Water Equivalent The water equivalent of a substance is defined as the mass of water that would absorb the same amount of heat as the substance for a given temperature change. It can be calculated using the formula: \[ \text{Water Equivalent} = \text{Mass of the substance} \times \text{Specific heat of the substance} \] ### Step 2: Identify Given Values - Mass of aluminum vessel, \( m = 1 \, \text{kg} = 1000 \, \text{g} \) - Specific heat of aluminum, \( c = 0.25 \, \text{cal/g}^\circ C \) ### Step 3: Calculate the Water Equivalent Using the formula for water equivalent: \[ \text{Water Equivalent} = m \times c \] Substituting the values: \[ \text{Water Equivalent} = 1000 \, \text{g} \times 0.25 \, \text{cal/g}^\circ C \] \[ \text{Water Equivalent} = 250 \, \text{g} \] ### Step 4: Conclusion The water equivalent of the aluminum vessel of mass 1 kilogram is \( 250 \, \text{g} \). ---

To find the water equivalent of an aluminum vessel with a mass of 1 kilogram, we can follow these steps: ### Step 1: Understand the Concept of Water Equivalent The water equivalent of a substance is defined as the mass of water that would absorb the same amount of heat as the substance for a given temperature change. It can be calculated using the formula: \[ \text{Water Equivalent} = \text{Mass of the substance} \times \text{Specific heat of the substance} \] ...
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

A brass ball of mass 100g is heated to 100^(@)"C" and then dropped into 200g of turpentine in a calorimeter at 15^(@)"C" . The final temperature is found to be 23^(@)"C" . Take specific heat of brass as 0.092 "cal"//"g"^(@)"C" and water equivalent of calorimeter as 4g. Heat lost by the ball is approximately

A brass ball of mass 100g is heated to 100^(@)"C" and then dropped into 200g of turpentine in a calorimeter at 15^(@)"C" . The final temperature is found to be 23^(@)"C" . Take specific heat of brass as 0.092 "cal"//"g"^(@)"C" and water equivalent of calorimeter as 4g. Heat gained by turpentine and calorimeter is approximately

The water equivalent of 20 g of aluminium (specific heat 0.2" cal"//g-""^(@)C ), is :-

The water equivalent of 50g of aluminium (Specific heat is 0.2 cal g^-1 °C^-1 )

A brass ball of mass 100g is heated to 100^(@)"C" and then dropped into 200g of turpentine in a calorimeter at 15^(@)"C" . The final temperature is found to be 23^(@)"C" . Take specific heat of brass as 0.092 "cal"//"g"^(@)"C" and water equivalent of calorimeter as 4g. The specific heat of turpentine is

A ball of mass 20 g and specific heat capacity 0.1 cal//g –.^(@)C . The water equivalent of ball is

The specific heat of a metal is 0.16 cal g_1 . The equivalent mass of the metal is 20.04. What is the correct atomic mass of the metal in grams?