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5 gm of steam at 100^@ C is passed into ...

`5 gm` of steam at `100^@ C` is passed into calorimeter containing liquid. Temperature of liquid rises from `32^@ C` to `40^@ C`. Then water equivalent of calorimeter and contents is

A

40 g

B

375 g

C

300 g

D

160 g

Text Solution

Verified by Experts

The correct Answer is:
B
Heat lost by steam = Heat gained by the calorimeter and contents.
`m_(steam) xx L_(v)+m_(s) xx1(100^@-40^@)=mS(40^@-32^@)`.
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