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Steam is passes into 22 g of water at 20...

Steam is passes into 22 g of water at `20^@C`. The mass of water that will be present when the water acquires a temperature of `90^@C` (Latent heat of steam is `540 cal//g`) is

A

`27.33 g`

B

`24.8 g`

C

`2.8 g`

D

`30 g`

Text Solution

Verified by Experts

The correct Answer is:
B
`m_(steam)L_(v) +m_(steam) S_(w) (100\^@ -90^@)`
=`m_(w)S_(w)(90^@-20^@)`
`m_(steam)` = mass f steam converted into water
:. Mass of water `= 22 g + m_(steam)`.
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