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A radiation of wave length 2500A^(0) is ...

A radiation of wave length `2500A^(0)` is incident on a metal plate whose work function is `3.5eV`. Then the potential required to stop the fastest photo electrons emitted by the surface is `(h=6.63xx10^(-34)Js & c=3xx10^(8)m//s)`

A

`1.86V`

B

`3.00V`

C

`1.46V`

D

`2.15V`

Text Solution

Verified by Experts

The correct Answer is:
C
`V_(0)e=[(12400)/(lambda "in"A^(0))-omega_(0)]eV`
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